Which choice is equivalent to the expression below?10 (i) √3x 2 10x 7√3 = 0 (ii) 4√3x 2 5x – 2√3 = 0 Solution (i) √3x 2 10x 7√3 = 0 Let us factorize the given expression, √3x 2 3x 7x 7√3 = 0 As √3 × 7√3 = 3 × 7 = 21 and 3 7 = 10 √3x(x √3) 7(x √3) = 0 (√3x 7) (x √3) = 0 So now, (√3x 7) = 0 or (x √3) = 0 √3x 2√3 x 2 – 5x √3 = 0 Compare given equation with the general form of quadratic equation, which is ax 2 bx c = 0 a = 2√3, b = – 5 , c = √3 Find Discriminant D = b 2 – 4ac = (– 5) 2 – 4 x 2√3 x √3 = 25 – 24 = 1 > 0 Roots of equation are

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2x^2+3x-7=x^2+5x+39
2x^2+3x-7=x^2+5x+39-(3 3 x 3 3x) 2 = 0 Step 2 Polynomial Roots Calculator 21 Find roots (zeroes) of F(x) = 27x 3 3x2 Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned toolsCâu 1√x²3 Câu 2√x²2x3 Câu 3√x(x2) Câu 4√x²5x6 (√ dấu này là căn bậc 2 nha giúp em vs)




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i 3x 2 – 5x 7 = 0 ii √3 x 2 √2 x – 2 √3 = 0 iii m 2 – 2m 1 = 0 Solution i 3x 2 – 5x 7 = 0 Comparing the above equation with ax 2 bx c = 0, we get a = 3, b = 5, c = 7 ∴ ∆ = b 2 – 4ac = (5) 24 × 3 × 7 = 25 – 84 ∴ ∆ = 59 ∴ ∆ < 0 ∴ Roots of the given quadratic equation are not real ii √3 x Find an answer to your question 4x^24x3 5x^248x 2√3x^25x√3 pagalmath3403 is waiting for your help Add your answer and earn pointsFactorise 2√3x2 X 5√3
About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us Creators4x34x23x3=0 Three solutions were found x = 1 x = ±√ 0750 = ± Step by step solution Step 1 Equation at the end of step 1 (((4 • (x3)) 22x2) 3x) 3 = 0 Step 2Lim X→2 =( √(2x²3x2)2)/(√(3x²5x1)1) Pergunta de ideia deongarato
Factorise x 2 3√3x30 x²3√3x30=x²5√3x2√3x Please scroll down to see the correct answer and solution guide Disclaimer FAQwalla is purely a usergenerated content site and so, the questions & answers posted here will solely reflect the views of the usersQ13 The denominator of a rational number is greater than its numerator by 8 If the numerator is increased by 17 and the denominator is increased by 1, the number becomes 3/2




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Discriminant of the quadratic equation √5x 2 3 √3x 2 √5 = 0 is 1) 67 2) 76 3) 67 4) 76Find the roots of the equation 2√3 x^2 – 5x √3 = 0 if they exist, by applying the quadratic formulaClick here👆to get an answer to your question ️ Factorise 4√(3)x^2 5x 2√(3)




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I presume that this is supposed to be a quadratic expression, thus the first term should be 2√3x^2 Let's use this quadratic expression in an equation 2 3 x 2 − 5 x 3 = 0 Now, if we have a quadratic equation in the form a x 2 b x c = 0 we have a simple formula to determine the roots of the quadratic x = − b ± b 2 − 4 a c 2 a Find the zeroes of the polynomial f(x) = 2√3x^2 ˗ 5x √3 and verify the relation between its zeroes and coefficients 3x 3 – x 2 – 10x Question 35 Solution Question 36 Solution Question 37 Solution √2x 2 3x √2 Question 38 Solution √5x 2 2x – 3√5 Question 39 Solution 2a 2 3√3x 3 Question 40 Solution 2√3x² x – 5√3 Question 41 Solution 5√5x 2 x 3√5 Question 42 Solution 7√x² – 10x – 4√2




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Click here👆to get an answer to your question ️ Factorize 2√(3)x^2 5x √(3)Here is the technique and how to solve this integration#Calculus#Formula#Technique#SubstitutionFind the zeroes of the polynomial f(x) = 2√3x 2 ˗ 5x √3 and verify the relation between its zeroes and coefficients polynomials;




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Is done on EduRev Study Group by Class 10 Students The Questions and Answers of Solve the equation 4√3x square 5x2√3?Are solved by group of students and teacher of Class 10, which is also the largest student community of Class 10 Find the roots of the following quadratic equation 2√3x 25x √3 = 0 Solution Question 129 Find the roots of the following quadratic equation x 2 – 3√5x 10 = 0 Solution Question 130 Find the roots of the following quadratic equation√3x 22√2x2√3=0 Solution Question 1310 votes 1 answerClick here 👆 to get an answer to your question ️ 2√3x^25x√3 factories it hiteshkr4



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Solution Evaluate Lim X 3x 4 2x 2 7 5x 3 X 3